ok i have molality is 1.05, mole fraction is 0.076, and wt% is 2.87 and solvent is C6H6 what is solute?
What an interesting problem. I don't think I've seen anything like this in my entire career. I'll get you started.
wt% = 2.87 which means
2.87 g solute/(100 g solution)]*100 = 2.87
That is [(2.87g solute)/(2.87 solute + 97.13 g C6H6)]* 100
So we multiply by 10 to get 28.7 g solute/971.3 g C6H6 = 29.55 that is the same as the 1.05 m solution and molar mass about 27.33. So you need to come up with something that has a molar mass of about 27.3. N2 is close. CO is close. C2H4 is close.