After a snowstorm a boy and girl decide to have a snowball fight. The girl uses a large slingshot to shoot snowballs at the boy. Assume that the girl fires each snowball at an angle 0 from the ground and that the snowball travel with an initial velocity of V0..

1.in terms of the inital velocity V0 and the lanch angle 0 for what amount of time (delta T) will a snowball tracel bfore it reaches its minimum height ab0ve the grpond

To find the amount of time a snowball travels before it reaches its minimum height above the ground, we can use the concept of projectile motion. The motion of the snowball can be broken down into horizontal and vertical components.

First, let's consider the vertical motion of the snowball. When the snowball is projected upwards, it will follow a parabolic trajectory due to gravity. The time taken for the snowball to reach its highest point (where its vertical velocity becomes zero) is given by:

T = V₀sin(θ) / g

where V₀ is the initial velocity of the snowball and θ is the launch angle, and g is the acceleration due to gravity (approximately 9.8 m/s²).

Now, to calculate the total time it takes for the snowball to reach its minimum height, we double the time taken to reach the highest point, as the snowball takes the same amount of time to descend from the highest point to its minimum height:

Total time = 2 * T = 2 * (V₀sin(θ) / g)

So, in terms of the initial velocity V₀ and the launch angle θ, the amount of time (ΔT) it takes for a snowball to reach its minimum height above the ground can be calculated using the formula:

ΔT = 2 * (V₀sin(θ) / g)

the height in meters is

h(t) = (Vo sinθ)t - 4.9t^2

Now just find t when h=0.

You sure overload the symbol 0.