Given that log y = log (10^n) solve for n.
To solve for \(n\) in the equation \(\log y = \log (10^n)\), we can use the property of logarithms that states that \(\log_b(a^c) = c \cdot \log_b(a)\).
Using this property, we can rewrite the equation as \( \log y = n \cdot \log 10 \).
Now, since \(\log 10\) is equal to 1, we can simplify the equation to \(\log y = n \cdot 1\).
Since any number multiplied by 1 is equal to itself, we can further simplify the equation to \(\log y = n\).
Therefore, \(n = \log y\).
Hence, the value of \(n\) is equal to the logarithm of \(y\).