When 80.0 mL of HCl is added to 80.0 mL of NH3OH, the temperature increases 2.5 celsius. Assuming the final solution has the same specific heat capacity as liquid water, the heat produced in the reaction between two solutions is:
I don't get how to find the moles and mass
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To find the moles and mass involved in the reaction between HCl and NH3OH, you need to use the given volume and concentration of each solution. Here's how you can calculate it:
1. Convert the volume of each solution to liters:
- Volume of HCl = 80.0 mL = 80.0 mL * (1 L/1000 mL) = 0.080 L
- Volume of NH3OH = 80.0 mL = 80.0 mL * (1 L/1000 mL) = 0.080 L
2. Determine the molarity (concentration) of each solution. If you have the molarity (M), you can directly calculate the moles. However, if you have a different concentration unit, such as percent by mass or weight/volume, you need to convert it to molarity using the molar mass.
3. Find the moles of HCl:
- Given: No concentration provided for HCl. If you have the concentration, you can multiply the concentration (M) by the volume in liters (0.080 L) to get moles. If not, you may need additional information or clarification to calculate the moles.
4. Find the moles of NH3OH:
- Given: No concentration provided for NH3OH. If you have the concentration, you can multiply the concentration (M) by the volume in liters (0.080 L) to get moles. If not, you may need additional information or clarification to calculate the moles.
Without the concentrations of HCl and NH3OH, it's not possible to calculate the moles and mass involved in the reaction. Please provide the concentrations or any additional information you may have related to the reaction.