The balanced net ionic equation resulting from addition of aqueous hydrochloric acid to solid chromium(III) hydroxide is:

A. Cr(OH)3 (s) + 3 HCl (aq) 3 H2O (l) + CrCl3 (aq)
B. Cr(OH)3 (s) + 3 Cl- (aq) 3 OH- (l) + CrCl3 (aq)
C. Cr(OH)3 (s) + 3 H+ (aq) + 3 Cl- (aq) 3 H2O (l) + Cr3+(aq) + 3 Cl- (aq)
D. Cr(OH)3 (s) + 3 H+(aq) 3 H2O(l) + Cr3+(aq)
E. Cr(OH)3 (s) + 3 H+(aq) + 3 Cl- (aq) 3 H2O (l) + CrCl3 (s)

this mofo forgot the damn arrows lmfaoooo

The answer is D tho. I'm mad smart, so you can trust.

Also why Dr. Bob be getting downvoted to sht?

To determine the balanced net ionic equation resulting from the addition of aqueous hydrochloric acid (HCl) to solid chromium(III) hydroxide (Cr(OH)3), we need to identify the ions present in the reaction and balance them.

The chemical formula for hydrochloric acid is HCl, and when it is dissolved in water it dissociates into H+ and Cl- ions. The solid chromium(III) hydroxide, Cr(OH)3, also dissociates into ions when it is in aqueous form. The ions formed are Cr3+ and OH-.

The balanced net ionic equation can be determined by canceling out spectator ions, which are ions that appear on both sides of the equation and do not participate in the reaction.

In this case, the net ionic equation is:

Cr(OH)3 (s) + 3 H+(aq) 3 H2O(l) + Cr3+(aq)

Therefore, the correct answer is option D:

D. Cr(OH)3 (s) + 3 H+(aq) 3 H2O(l) + Cr3+(aq)

To find the balanced net ionic equation resulting from the addition of hydrochloric acid (HCl) to chromium(III) hydroxide (Cr(OH)3), you need to identify the ions present in the reactants and determine the products formed.

First, let's break down the compounds into their respective ions:

Chromium(III) hydroxide (Cr(OH)3) dissociates into Cr3+ ions and OH- ions.

Hydrochloric acid (HCl) dissociates into H+ ions and Cl- ions.

Now, we can write the ionic equation by swapping the ions and balancing the charges:

Cr(OH)3 (s) + 3 H+ (aq) + 3 Cl- (aq) → 3 H2O (l) + Cr3+(aq) + 3 Cl- (aq)

In the above equation, the H+ ions and Cl- ions remain unchanged on both sides of the equation. These are spectator ions and can be canceled out.

So, the net ionic equation is:

Cr(OH)3 (s) + 3 H+ (aq) → 3 H2O (l) + Cr3+(aq)

Therefore, the correct answer is option D:

Cr(OH)3 (s) + 3 H+(aq) → 3 H2O(l) + Cr3+(aq)

It would help if I knew what you don't understand about this. Also it would help if you found and used the arrow key(s) To write the net ionic equation you balance the molecular equation (which happens to be A) as step 1, for step 2 convert the molecular equation into a full ionic equation, and for step 3 cancel any materials common to both sides to leave the net ionic equation.