What is the wavelength of visible light emit- ted at 4.2 × 108 MHz?
Use the wave equation
frequency*wevelength=speedoflight
To find the wavelength of visible light emitted at a frequency of 4.2 × 10^8 MHz, we can use the formula:
λ = c / f
Where:
λ is the wavelength
c is the speed of light (approximately 3.00 × 10^8 m/s)
f is the frequency in hertz (Hz)
First, we need to convert the frequency from megahertz (MHz) to hertz (Hz) by multiplying it by 10^6:
f = 4.2 × 10^8 MHz × 10^6 Hz/MHz = 4.2 × 10^14 Hz
Now, we can substitute the values into the wavelength formula:
λ = (3.00 × 10^8 m/s) / (4.2 × 10^14 Hz)
Dividing both the numerator and the denominator by 10^14:
λ ≈ (3.00 / 4.2) × 10^-6 m = 0.714 × 10^-6 m
Finally, we can simplify the notation:
λ ≈ 7.14 × 10^-7 m
Therefore, the wavelength of visible light emitted at a frequency of 4.2 × 10^8 MHz is approximately 7.14 × 10^-7 meters (or 714 nanometers).