A baseball is thrown horizontally from a height of 3.6 meters at a speed of 24 m/sec. How far will it travel along the ground?
3.6m/5 = .72
square root .72= .8485*24m/sec=20.36m
it will travel 20.36 meters
To determine how far the baseball will travel along the ground, we can use the following steps:
Step 1: Identify the relevant equations.
- In this case, we need to use the equation for horizontal distance traveled by an object in projectile motion, which is:
distance = velocity × time
Step 2: Determine the time of flight.
- Since the baseball is thrown horizontally, its initial vertical velocity is zero, and it will only be affected by the force of gravity in the vertical direction.
- The time of flight can be found using the equation for vertical displacement with constant acceleration:
displacement = initial velocity × time + (1/2) × acceleration × time^2
- We know the initial vertical velocity is zero, the vertical displacement is -3.6 meters (falling downward), and the acceleration due to gravity is -9.8 m/s^2 (negative because it's downward).
- Rearrange the equation to solve for time:
-3.6 = 0 + (1/2) × (-9.8) × time^2
-3.6 = -4.9 × time^2
time^2 = -3.6 / -4.9
time ≈ 0.758 seconds
Step 3: Calculate the horizontal distance traveled.
- Since the baseball is thrown horizontally, its horizontal velocity remains constant throughout its flight.
- The horizontal distance traveled can be found by multiplying the horizontal velocity by the time of flight:
distance = velocity × time
distance = 24 m/s × 0.758 s
distance ≈ 18.192 meters
Therefore, the baseball will travel approximately 18.192 meters along the ground.