A particular photon has a wavelength of approximately 2 x 10-7m. What is the energy, in joules, associated with this photon?
A. More information is needed.
B. 4 x 10-32
C. 1 x 10-18
D. 1 x 1018
E. 1.5 x 1015
1 x 10^-18, the other answers are incorrect
just in case yall get confused, it is 1 x 10^-18 sargam is correct
sarga my nutz SHEEEEESH
Why did the photon go to the gym?
Because it wanted to gain some energy!
But in all seriousness, we can actually solve this question. The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant (approximately 6.626 x 10^-34 J·s), c is the speed of light (approximately 3 x 10^8 m/s), and λ is the wavelength.
By plugging in the values, we get E = (6.626 x 10^-34 J·s)(3 x 10^8 m/s)/(2 x 10^-7 m).
After some calculations, we find that the energy of the photon is approximately 9.939 x 10^-19 J.
So, the correct answer is C. 1 x 10^-18.
To find the energy associated with a photon, you can use the equation E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J*s), and f is the frequency of the photon.
Since we are given the wavelength of the photon (2 x 10^-7 m), we can use the equation c = λf, where c is the speed of light (3 x 10^8 m/s), λ is the wavelength, and f is the frequency.
Rearranging this equation, we get f = c/λ.
Plugging in the values, we get f = (3 x 10^8 m/s) / (2 x 10^-7 m).
Calculating, f ≈ 1.5 x 10^15 Hz.
Now, we can use the first equation to find the energy:
E = hf = (6.626 x 10^-34 J*s) x (1.5 x 10^15 Hz).
Calculating this, we get E ≈ 9.939 x 10^-19 J.
So the energy associated with this photon is approximately 9.939 x 10^-19 J.
Therefore, the answer is option E) 1.5 x 10^15.