"Find the total energy lost by the contents of a Styrofoam picnic cooler when a 3.60 kg block of ice placed inside the cooler completely melts (at 0 Celsius). The ice had an initial temperature of -10.00 Celsius."
I did this question and i got 73080J but I'm not sure if i did it right, can u please tell me the steps!!!
thanks in advance
q1 = heat to raise T from -10 to zero.
q1 = mass ice in grams x specific heat solid ice x 10
q2 = heat to melt ice
q2 = mass ice x heat fusion.
Add q1 + q2 = total q.
q1=72360J n q2=21672
q=94032J
is that right DrBob222
No. The 72,360 J is right for the q1 part. I don't know where the 21,573 came from.
For q2 I got 1204.66 (rounded) but now I’m confused a bit
To find the total energy lost by the contents of the Styrofoam picnic cooler when the block of ice completely melts, we need to calculate the energy required to warm the ice from -10.00 Celsius to 0 Celsius and then the energy required to melt the ice at 0 Celsius.
Step 1: Calculate the energy required to warm the ice from -10.00 Celsius to 0 Celsius.
To calculate the energy required to warm the ice, we can use the specific heat capacity formula:
Q = mcΔT
Where:
Q is the energy transferred (in joules)
m is the mass of the ice (in kg)
c is the specific heat capacity of ice (in J/kg·C)
ΔT is the change in temperature (in Celsius)
The specific heat capacity of ice is approximately 2.09 J/g·C (or 2090 J/kg·C).
We need to convert the mass of the ice from grams to kilograms, so:
m = 3.60 kg
ΔT = 0 Celsius - (-10.00 Celsius) = 10.0 Celsius
Q = (m)(c)(ΔT)
= (3.60 kg)(2090 J/kg·C)(10.0 Celsius)
= 75480 J
Step 2: Calculate the energy required to melt the ice at 0 Celsius.
To calculate the energy required to melt the ice, we use the latent heat formula:
Q = mL
Where:
Q is the energy transferred (in joules)
m is the mass of the ice (in kg)
L is the latent heat of fusion of ice (in J/kg)
The latent heat of fusion of ice is approximately 334,000 J/kg.
Q = (m)(L)
= (3.60 kg)(334,000 J/kg)
= 1,202,400 J
Step 3: Find the total energy lost.
To find the total energy lost, we add together the energy required to warm the ice and the energy required to melt the ice:
Total energy lost = Energy to warm ice + Energy to melt ice
= 75480 J + 1,202,400 J
= 1276880 J
Therefore, the total energy lost by the contents of the Styrofoam picnic cooler when a 3.60 kg block of ice placed inside the cooler completely melts is 1,276,880 J (or approximately 1.28 MJ).