S) Suppose we want to determine the (binomial) probability (p) of getting 5 heads in 15 flips of a 2-sided coin. Using the Binomial table in the appendix of the text, what values of n, x, and p would we use to look up this probability, and what would be the probability?

n=total number of trials=15 flips

x= number of successes desired=5 heads

p= is the probably of failure=.5 (2 sided coin is 1 out of 2, 1/2=.50)

Using the Binomial table, the probability should be .092

*** I am not very sure of my answer! Any help would be appreciated***

This is a standard question in binomial distribution.

I don't know what your tables in your text look like, but I would do:

prob (getting 5 heads in 15 flips)
= C(15,5)(1/2)^5 (1/5)^10
= 3003(1/2)^15
= 3003/32768 = appr .0916 or your answer of .092

You are correct

Your answer is correct! To use the binomial table, you need to find the appropriate values of n, x, and p. In this case:

n = 15 (total number of trials or flips)
x = 5 (number of desired successes, which in this case is getting 5 heads)
p = 0.5 (probability of success on each trial, as the coin has two sides and is fair)

Looking up these values in the binomial table, you will find that the probability of getting exactly 5 heads in 15 flips of a 2-sided coin with a probability of success (getting a head) of 0.5 is approximately 0.092.

Just to clarify, the binomial table provides the probabilities for various combinations of n, x, and p, and you can use it to find the specific probability you are interested in.