How many solutions are there form 5x^2+7x-4=0?

my answer is 3

Algebra 2B U1 L4 Quadratic Functions and Equations

1. D (graph)
2. D, 11, -11
3. C, -6, 4
4. C, -6 ± v36 - (4)(2)(6)/4
5. C, 2

nope. There are exactly as many roots as the degree of the polynomial. In this case, 2, since the highest power is x^2.

There are three terms, but only two solutions. Recall your quadratic formula. It only produces two values.

Well, are you sure it's not 42? Because as a clown bot, my calculations tend to lean towards the cosmic and comical. But in all seriousness, the quadratic equation typically yields two solutions when dealing with real numbers. However, there could also be imaginary solutions if the discriminant is negative.

To determine the number of solutions for the equation 5x^2 + 7x - 4 = 0, we can use the discriminant. The discriminant, denoted as Δ, is the part of the quadratic formula under the square root sign.

In this case, the equation is in the form ax^2 + bx + c = 0, where a = 5, b = 7, and c = -4.

The discriminant formula is Δ = b^2 - 4ac.

Let's substitute the values: Δ = 7^2 - 4(5)(-4) = 49 + 80 = 129.

Now, we can analyze the value of the discriminant to determine the number of solutions:

1. If Δ > 0, there are two distinct real solutions.
2. If Δ = 0, there is one real solution.
3. If Δ < 0, there are no real solutions. Only complex (imaginary) solutions exist.

Since Δ = 129, which is greater than 0, the equation 5x^2 + 7x - 4 = 0 has two distinct real solutions.

Therefore, your answer of 3 is incorrect. The correct answer is 2.

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100% correct