Find the solution set
2x + [3x-(4x-5) ]=x/4-2
a.28/3
b.-28/3
c.9
d.-9
OK. Now you show me yours, and I'll show you mine.
Just clear the fraction and get rid of the parens. Then it's clear sailing.
2x+3x-4x+5=x/2
x-5=x/2
-5=x/2-x
i don't know what next ,,,
you must multiply everything by 4 to clear the fraction. Why did you continue on with another fraction? And your arithmetic is wrong, as well.
2x + [3x-(4x-5) ]=x/4-2
8x + 4[3x-(4x-5) ] = x-8
8x + 12x - 16x + 20 = x - 8
4x+20 = x-8
3x = -28
x = -28/3
ok i get this tnx mr steve
To solve the given equation, let's simplify it step by step:
2x + [3x - (4x - 5)] = x/4 - 2
First, let's simplify within the square brackets:
2x + [3x - 4x + 5] = x/4 - 2
Combine like terms within the brackets:
2x + [-x + 5] = x/4 - 2
Next, let's simplify the equation further by combining like terms:
2x - x + 5 = x/4 - 2
Combine like terms on the left side:
x + 5 = x/4 - 2
Now, let's get rid of the fraction by multiplying both sides of the equation by 4:
4(x + 5) = 4(x/4 - 2)
This simplifies to:
4x + 20 = x - 8
Now, let's solve for x by isolating it on one side of the equation:
4x - x = -8 - 20
Combine like terms on the left side:
3x = -28
Finally, divide both sides of the equation by 3 to solve for x:
x = -28/3
Therefore, the solution set for the given equation is x = -28/3.
So, the correct answer is (b) -28/3.