The potential difference between a storm
cloud and the ground is 2.13 × 108 V.
If a bolt carrying 2 C falls from a cloud to Earth, what is the magnitude of the change of potential energy of the charge?
Answer in units of J.
Well, that's quite a shocking question! Let's calculate the magnitude of the change in potential energy of the charge.
The change in potential energy of the charge can be found using the formula:
Change in potential energy = charge × potential difference
Given that the charge is 2 C and the potential difference is 2.13 × 10^8 V, we can plug in the values:
Change in potential energy = 2 C × 2.13 × 10^8 V
Calculating this, we get:
Change in potential energy = 4.26 × 10^8 J
So, the magnitude of the change in potential energy of the charge is 4.26 × 10^8 J. That's quite an electrifying amount!
The magnitude of the change in potential energy of the charge can be calculated using the formula:
Change in potential energy = charge (Q) * potential difference (V)
Given:
Charge (Q) = 2 C
Potential difference (V) = 2.13 × 10^8 V
Substituting the values into the formula, we get:
Change in potential energy = 2 C * 2.13 × 10^8 V
Calculating the expression:
Change in potential energy = 4.26 × 10^8 C * V
The unit of charge is Coulombs (C), and the unit of potential difference is Volts (V). When multiplied together, the units cancel out, resulting in the unit of Joules (J).
Therefore, the magnitude of the change in potential energy of the charge is 4.26 × 10^8 J.
To find the magnitude of the change in potential energy, we can use the equation:
ΔPE = q * ΔV
Where:
ΔPE is the change in potential energy
q is the charge of the bolt (2 C)
ΔV is the potential difference (2.13 × 10^8 V)
Substituting the values into the equation, we have:
ΔPE = (2 C) * (2.13 × 10^8 V)
Calculating the right-hand side of the equation:
ΔPE = (2 C) * (2.13 × 10^8 V)
= 4.26 × 10^8 C * V
Since the unit of potential energy is joules (J), we need to convert the charge-voltage product (C * V) to joules by recognizing that 1 volt-coulomb (V * C) is equal to 1 joule (J). Therefore:
ΔPE = 4.26 × 10^8 J
So, the magnitude of the change in potential energy of the charge is 4.26 × 10^8 J.
Do not understand your notation.
Do you mean
2.13 * 10^8 Volts ????
anyway
energy in Joules = potential in Volts * charge in Coulombs