While rearranging a dorm room, a student does 312 J of work in moving a desk 2.0 m. What was the magnitude of the applied horizontal force?

To find the magnitude of the applied horizontal force, we can use the formula for work:

Work = Force * Distance * cos(θ)

In this case, the work done is 312 J and the distance moved is 2.0 m. We need to find the force. However, we don't have the angle (θ) given. Since the problem mentions that the desk is being moved horizontally, we can assume that the angle between the applied force and the direction of motion is 0 degrees.

Therefore, cos(0) = 1, and the formula simplifies to:

Work = Force * Distance

Plugging in the values we have:

312 J = Force * 2.0 m

Now we can rearrange the equation to solve for the force:

Force = Work / Distance
Force = 312 J / 2.0 m

Calculating the force:

Force = 156 N

Therefore, the magnitude of the applied horizontal force is 156 N.

To find the magnitude of the applied horizontal force, we need to use the equation W = F*d, where W is the work done, F is the applied force, and d is the displacement.

Given that the work done is 312 J and the displacement is 2.0 m, we can rearrange the equation to solve for F.

F = W / d

Plugging in the values, we get:

F = 312 J / 2.0 m

So the magnitude of the applied horizontal force is 156 N.

W=Fd

312J=F(2.0m)
F=(312J)/(2.0m)

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