7^-(1/5) / 7^-(7/5) * 7^3/5 can be simplified as 7^a/b where a and b are positive integers.
find a*b-a
answer:
7^-(1/5) / 7^-(7/5) * 7^3/5
7^5/7(5/7) * 7 ^3/5 <- plz explain this part?
7^(8/5-3/5)=7*5/5
Just add up all the powers of 7:
7^[(-1/5)-(-7/5)+(3/5)]
= 7^((-1+7+3)/5)
= 7^(9/5)
The line in question is wrong.
1/7^(-7/5) is NOT 7^(5/7)
it is 7^(7/5)
7^(-1/5) is NOT 7^5
it 1/7^(1/5)
Reciprocals just cause the exponent to be minus what it was, not the reciprocal. Better review the rules of exponents again.
so, a*b-a = 45-9 = 36