a charge of 4 nc is located at the origin and -5nc is located at x axis.find yhe electric intencity at y =2m along y-axis?

To find the electric intensity at a point due to multiple charges, you need to calculate the electric field produced by each charge and then add them up vectorially.

Let's consider the two charges:

Charge 1: 4 nC at the origin (0, 0)
Charge 2: -5 nC at a point on the x-axis, let's call it P(x, 0)

Step 1: Calculate the electric field at the point P due to Charge 1:
The formula for the electric field due to a point charge is given by:

E = k * q / r^2

where E is the electric field, k is the electrostatic constant (9 * 10^9 Nm^2/C^2), q is the charge, and r is the distance between the charge and the point where the electric field is being calculated.

In this case, Charge 1 has a magnitude of 4 nC and is located at the origin, so the distance r is equal to the distance between the origin and point P, which is just x because the y-coordinate of P is 0.

Thus, the electric field due to Charge 1 at point P is given by:

E1 = k * q1 / x^2

Step 2: Calculate the electric field at the point P due to Charge 2:
The distance between Charge 2 and point P is given by the y-coordinate of P, which is 2 m.

Thus, the electric field due to Charge 2 at point P is given by:

E2 = k * q2 / r^2

where q2 is the magnitude of Charge 2 (5 nC) and r is the distance between Charge 2 and point P, which is 2 m.

Step 3: Calculate the net electric field at point P by adding the electric fields due to both charges:
Since electric field is a vector quantity, we need to add the electric fields due to each charge vectorially. This means we need to consider both the magnitudes and directions of the electric fields.

In this case, the electric field due to Charge 1 is directed towards the origin (opposite to the direction of x-axis), and the electric field due to Charge 2 is directed towards the negative y-axis (opposite to the direction of positive y-axis).

To add these vectorially, you need to take into account the signs and directions. In this case, since the charges have opposite signs, the electric fields will have opposite directions.

So, the net electric field at point P is given by:

E_net = E1 - E2

Step 4: Calculate the electric intensity:
Electric intensity is defined as the magnitude of electric field. So, to find the electric intensity at point P, simply take the magnitude of the net electric field:

I = |E_net|

Therefore, using the above steps, you can calculate the electric intensity at y = 2 m along the y-axis by evaluating the above equations for the given values of x and the given charges.