a 1.32g sample on unknown containing KHP as a component was titrated with 22.48mL of 0.105 M NaOH to a pheolphthalein end point. what is the weight percent of KHP in the unknown sample?

KHP + NaOH ==> NaKP + H2O

mols NaOH = M x L = ?
mols KHP = mols NaOH since the reaction is 1:1
grams KHP = mols KHP x molar mass KHP.
%KHP = (mass KHP/mass sample)*100 = ?

To determine the weight percent of KHP (potassium hydrogen phthalate) in the unknown sample, we can use the concept of stoichiometry and the data provided.

Here's how you can calculate the weight percent:

1. Calculate the number of moles of NaOH used:
Moles of NaOH = Volume of NaOH (L) × Molarity of NaOH (mol/L)
Moles of NaOH = 22.48 mL × (1 L / 1000 mL) × 0.105 mol/L

2. Determine the molar ratio between NaOH and KHP in the balanced equation:
The balanced equation for the reaction between NaOH and KHP is:
NaOH + KHP → NaKP + H2O
From the balanced equation, we see that 1 mole of NaOH reacts with 1 mole of KHP.

3. Calculate the number of moles of KHP:
Moles of KHP = Moles of NaOH

4. Determine the molar mass of KHP (Molar mass KHP = 204.22 g/mol) and calculate the weight of KHP:
Weight of KHP = Moles of KHP × Molar mass of KHP

5. Calculate the weight percent of KHP in the unknown sample:
Weight percent of KHP = (Weight of KHP / Weight of the unknown sample) × 100

Now let's substitute the given values into the equations and calculate the weight percent:

Moles of NaOH = 22.48 mL × (1 L / 1000 mL) × 0.105 mol/L = 0.00236 mol
Moles of KHP = Moles of NaOH = 0.00236 mol
Weight of KHP = 0.00236 mol × 204.22 g/mol = 0.481 g
Weight percent of KHP = (0.481 g / 1.32 g) × 100 = 36.44%

Therefore, the weight percent of KHP in the unknown sample is approximately 36.44%.