One gram of palladium has 5.66×10^21 atoms, and each palladium atom has 46 electrons. How many electrons are contained in 7.00g of palladium? The elemental charge is1.6×10^−19C. Answer in units of electrons.
The answer is 1.82252x10^24 for Part A. i need help with part B.
b)What is the total charge of these electrons? Answer in units of C.
I Did 1.82252x10^24 x 1.6x10^-19 and i got 291603.2 but it's wrong. can someone help me with this part?
7grams * 5.66*10^21atoms/gram * 46e/atom
= 1.82252*10^24 Electrons.
b. 1.82252*10^24e * 1.6*10^-19C/e =
2.916*10^5 C. = Your answer.
To calculate the total charge of the electrons in 7.00g of palladium, you need to multiply the number of electrons by the elemental charge. Let's break down the calculation step by step:
First, let's calculate the number of electrons:
Given that 1 gram of palladium has 5.66×10^21 atoms and each palladium atom has 46 electrons, we can calculate the number of electrons in 1 gram of palladium:
1 gram of palladium -> 5.66×10^21 atoms
1 atom -> 46 electrons
Using these conversion factors, we can find the number of electrons in 1 gram of palladium:
(1 gram of palladium) × (5.66×10^21 atoms / 1 gram) × (46 electrons / 1 atom)
This simplifies to:
5.66×10^21 × 46 = 2.6056×10^23 electrons
Now, to find the number of electrons in 7.00g of palladium, we can multiply the number of electrons in 1 gram by 7:
(2.6056×10^23 electrons) × (7 grams)
This gives us:
1.82492×10^24 electrons
Now let's move on to calculating the total charge:
Given that the elemental charge is 1.6×10^−19 C, we want to find the total charge of the electrons in 7.00g of palladium. To do this, we need to multiply the number of electrons by the elemental charge:
(1.82492×10^24 electrons) × (1.6×10^−19 C / 1 electron)
This simplifies to:
2.919872×10^5 C
Therefore, the total charge of the electrons in 7.00g of palladium is approximately 2.919872×10^5 coulombs (C).