at STP , what is the volume of 7.08 mole of Nitrogen gas ?
To find the volume of 7.08 moles of nitrogen gas at standard temperature and pressure (STP), you'll first need to know the molar volume of gases at STP.
At STP, the molar volume of any ideal gas is approximately 22.4 liters. This means that one mole of any ideal gas occupies 22.4 liters of space.
Now, you can use this information to find the volume of 7.08 moles of nitrogen gas.
Volume = Number of moles × Molar volume
Volume = 7.08 moles × 22.4 liters/mole
Volume = 158.592 liters
Therefore, the volume of 7.08 moles of nitrogen gas at STP is approximately 158.592 liters.