A hailstone traveling with a velocity of 43 meters/second comes to a virtual stop 0.28 seconds after hitting water. What is the magnitude of its acceleration in the water?

a. 12 meters/second2
b. 1.5 × 102 meters/second2
c. 78.6 meters/second2
d. 6.5 × 10-3 meters/second2

a. 12 meters/seconds

To find the magnitude of the acceleration in water, we need to use the following equation:

v = u + at

Where:
v = final velocity after hitting the water (which is 0 m/s because it comes to a virtual stop)
u = initial velocity before hitting the water (43 m/s)
a = acceleration in the water
t = time taken to come to a stop (0.28 seconds)

Rearranging the equation, we get:

a = (v - u) / t

Substituting the given values, we have:

a = (0 - 43) / 0.28

Calculating this, we get:

a = -43 / 0.28

a ≈ -153.571 m/s²

Since acceleration is a vector and magnitude only considers the absolute value, the magnitude of acceleration is the positive value of -153.571 m/s².

Therefore, the magnitude of acceleration in the water is approximately 153.571 m/s².

None of the given answer choices match this value, so there may be an error in the provided options.

To find the magnitude of the acceleration, we can use the formula:

Acceleration = Change in velocity / Change in time

In this case, the change in velocity is the final velocity minus the initial velocity. The final velocity is 0 meters/second because the hailstone comes to a stop, and the initial velocity is 43 meters/second. The change in time is given as 0.28 seconds.

Using the formula, we can calculate the acceleration:

Acceleration = (0 meters/second - 43 meters/second) / 0.28 seconds

Acceleration = (-43 meters/second) / 0.28 seconds

Acceleration = -153.57 meters/second^2

The magnitude of the acceleration is the absolute value of the negative value, so the magnitude is 153.57 meters/second^2.

Therefore, none of the given options (a, b, c, d) match the magnitude of the acceleration.

v = 43 - 0.28a

so, what is a if v=0?