Upon decomposition, one sample of magnesium fluoride produced 1.55 kg of Magnesium and 2.42 kg of fluoride. A second sample produced 1.10kg of magnesium. How much fluoride (in grams) did the second sample produced?
Probably none. I'm sure you meant FLUORINE and not fluoride.
Just set up a proportion.
(1.55/1.10) = (2.42/x) and solve for x
To find out how much fluoride the second sample produced, we first need to determine the ratio of magnesium to fluoride in the first sample. From the information given, we know that 1.55 kg of magnesium and 2.42 kg of fluoride were produced.
Let's calculate the ratio:
Ratio of magnesium to fluoride = Mass of magnesium / Mass of fluoride
Ratio of magnesium to fluoride = 1.55 kg / 2.42 kg
Ratio of magnesium to fluoride = 0.64
Now we can use the ratio to find out how much fluoride the second sample produced.
Mass of fluoride in the second sample = Ratio of magnesium to fluoride * Mass of magnesium in the second sample
Mass of fluoride in the second sample = 0.64 * 1.10 kg
Converting from kilograms to grams:
Mass of fluoride in the second sample = 640 g
Therefore, the second sample produced 640 grams of fluoride.
To find out how much fluoride the second sample produced, we need to determine the ratio of magnesium to fluoride in the first sample.
1. Begin by calculating the ratio of magnesium to fluoride in the first sample:
- Magnesium: 1.55 kg
- Fluoride: 2.42 kg
Divide the mass of magnesium by the mass of fluoride:
1.55 kg ÷ 2.42 kg ≈ 0.64
This ratio tells us that for every 0.64 kg of magnesium, we have 1 kg of fluoride.
2. Now, we can use this ratio to find out how much fluoride the second sample produced:
- Magnesium in the second sample: 1.10 kg
Multiply the mass of magnesium in the second sample by the ratio we calculated in step 1:
1.10 kg × 1 kg fluoride ÷ 0.64 kg magnesium ≈ 1.72 kg fluoride
3. Finally, convert the mass of fluoride from kilograms to grams:
1.72 kg ≈ 1720 g
Therefore, the second sample produced approximately 1720 grams of fluoride.