A 5.2 litre baloon at 900 torr of pressure. If the temp is kept constant and the pressure is reduced to 200 torr what is the voume in the balloon?
Is this a trick question? My instinct is to say the volume is the same, 5.2 litres.
Probably it isn't a trick question.
p1v1 = p2v2
You know p1 and v1 and p2, solve for v2.
Thank you. That was a big help. My Dad is trying to help me but he's been out of college more then 30 years.
I've been out more than 50. I know how he feels.
This is not a trick question! In this scenario, you are dealing with Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at a constant temperature. Boyle's Law can be expressed mathematically as:
P1 x V1 = P2 x V2
where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
Given that the initial volume is 5.2 litres (V1 = 5.2 L), the initial pressure is 900 torr (P1 = 900 torr), and the final pressure is reduced to 200 torr (P2 = 200 torr), we need to solve for the final volume (V2).
Using the equation P1 x V1 = P2 x V2, we can rearrange it to solve for V2:
V2 = (P1 x V1) / P2
Now, substitute the values:
V2 = (900 torr x 5.2 L) / 200 torr
V2 = 23.4 L / 200 torr
V2 = 0.117 L
Therefore, when the pressure is reduced to 200 torr, the volume in the balloon is approximately 0.117 litres.