a pool is 39.8 m long and 28.2 m wide. if the average depth of water is 4.90 ft, what is the mass (in kg) of water in the pool? enter your answer in scientific notation. the density of water is 1.0 g/mL
5.49e3
To find the mass of water in the pool, we need to calculate the volume of the pool and then convert it to mass using the density of water.
First, let's calculate the volume of the pool. The volume (V) of a rectangular prism (like a pool) is given by the formula:
V = length × width × height
In this case, the length is 39.8 m, the width is 28.2 m, and the average depth is 4.90 ft. However, since the density of water is given in g/mL, we need to convert the height from feet to meters.
1 ft = 0.3048 m
So, the height (h) in meters is:
h = 4.90 ft × 0.3048 m/ft = 1.49412 m
Now, we can substitute the values into the volume formula:
V = 39.8 m × 28.2 m × 1.49412 m = 16786.978 m³
The next step is to convert the volume from cubic meters to milliliters:
1 m³ = 1000 L = 1000,000 mL
So, the volume (V) in milliliters is:
V = 16786.978 m³ × 1000,000 mL/m³ = 16,786,978 mL
Finally, we can find the mass (m) of water using the formula:
m = density × volume
The density of water is given as 1.0 g/mL.
m = 1.0 g/mL × 16,786,978 mL = 16,786,978 g
Now, we need to convert the mass from grams to kilograms:
1 kg = 1000 g
So, the mass (m) in kilograms is:
m = 16,786,978 g ÷ 1000 = 16,786.978 kg
Therefore, the mass of water in the pool is 1.6786978 × 10^4 kg (in scientific notation).
Convert 39.8m 28.2m and 4.9 ft to cm.
Calculate volume = l x w x d = ? cc
Convert mass using density to get mass in grams and convert to kg.