the standard score for hours spent online at home for Minnesotans was 2.84. The mean equals 8.9 hours. Approximately how many hours do Minnesotan adults spend online at home.
Lacking data.
Z = (score-mean)/SD
2.84 = (score- 8.9)/SD
What is the SD (standard deviation)?
To approximate the number of hours Minnesota adults spend online at home, we can use the formula for standard score (z-score):
z = (x - μ) / σ
Where:
- x is the given standard score (2.84)
- μ is the mean (8.9 hours)
- σ is the standard deviation (not provided)
Since the standard deviation (σ) is not provided, we cannot directly solve for the number of hours. To approximate the answer, we will assume a standard deviation based on common knowledge or previous data.
Let's assume a standard deviation of 3. In statistical terms, this is a reasonable assumption for most data sets.
Using the formula, we can rearrange it to find the raw data:
x = z * σ + μ
Substituting the given values:
x = 2.84 * 3 + 8.9
x = 8.52 + 8.9
x ≈ 17.42
Therefore, using this approximation, Minnesotan adults spend approximately 17.42 hours online at home. However, please note that this answer is an estimation based on assumptions, and the precise value may vary depending on the actual standard deviation of the data set.