Carbon tetrachloride contains one carbon and four chlorine atoms. For this compound 11.818 g of chlorine combine with 1.000 g of C-12. Using this information, calculate the atomic mass of chlorine.
the unit is in amu unit
To calculate the atomic mass of chlorine, we need to find the total mass of chlorine atoms present in the compound.
Given that 11.818 g of chlorine (Cl) combines with 1.000 g of carbon-12 (C-12), we can calculate the number of moles of carbon and chlorine present.
1. Calculate the number of moles of carbon-12 (C-12):
- Atomic mass of carbon-12 = 12.01 g/mol (from the periodic table)
- Moles of carbon-12 = Mass of carbon-12 / Atomic mass of carbon-12
= 1.000 g / 12.01 g/mol
≈ 0.0832 moles
2. Calculate the number of moles of chlorine (Cl):
- Atomic mass of chlorine (Cl) = Unknown (to be calculated)
- Moles of chlorine (Cl) = Mass of chlorine (Cl) / Atomic mass of chlorine (Cl)
Let's denote the atomic mass of chlorine as x.
Using the given information, the equation becomes:
11.818 g / x = 0.0832 moles
Solving for x:
x = 11.818 g / 0.0832 moles
Calculating x using a calculator, we find:
x ≈ 141.99 g/mol
Therefore, the atomic mass of chlorine is approximately 141.99 g/mol.
To determine the atomic mass of an element, we can use the concept of the mole. The mole is a unit used to measure the amount of a substance, and it is equal to Avogadro's number (6.022 x 10^23) of particles.
First, we need to find the number of moles of chlorine and carbon in the given compounds.
The molar mass of carbon tetrachloride (CCl4) can be calculated by adding the atomic masses of carbon and chlorine.
- Atomic mass of carbon (C) = 12.01 g/mol
- Atomic mass of chlorine (Cl) = unknown
To calculate the number of moles of C and Cl atoms, we'll divide their masses by their respective molar masses:
- Moles of carbon (C) = 1.000 g / 12.01 g/mol
- Moles of chlorine (Cl) = 11.818 g / unknown g/mol
Since the compound has one carbon atom and four chlorine atoms, we can create a ratio between the moles of chlorine and carbon:
- Moles of Cl / Moles of C = 4 / 1
Now we substitute the moles calculated earlier into the above equation:
- (11.818 g / unknown g/mol) / (1.000 g / 12.01 g/mol) = 4 / 1
To solve for the unknown, we can cross multiply and rearrange the equation:
- (11.818 g) x (12.01 g/mol) = 4 x (1.000 g) x (unknown g/mol)
Simplifying, we get:
- unknown = (11.818 g x 12.01 g/mol) / (4 x 1.000 g) = 35.443 g/mol
Therefore, the atomic mass of chlorine is approximately 35.443 g/mol.