Henry Heavyweight weighs 1200N and stands on a pair of bathroom scales so that one scale reads twice as much as the other. What are the scale reading?
Scale1 = x Newton.
Scale2 = 2x Newton
x + 2x = 1200 N.
Solve for x.
400
Let's assume the scale that reads twice as much as the other scale as S1 and the other scale as S2.
Given that Henry Heavyweight weighs 1200N, we can write the equation:
S1 + S2 = 1200 (Equation 1)
We are also given that one scale reads twice as much as the other, so we can write the equation:
S1 = 2S2 (Equation 2)
Substitute the value of S1 from Equation 2 into Equation 1:
2S2 + S2 = 1200
3S2 = 1200
S2 = 400N
Substitute the value of S2 into Equation 2 to find S1:
S1 = 2S2
S1 = 2(400)
S1 = 800N
Therefore, the scale readings are:
Scale 1 (S1) = 800N
Scale 2 (S2) = 400N
To find the scale readings, let's assume that the reading of one scale is x N. Since the other scale reads twice as much, its reading would be 2x N.
Now, we know that the total weight of Henry is 1200N. This weight should be distributed between the two scales. Therefore, we can add the readings of the two scales to get the total weight:
x + 2x = 1200
Simplifying the equation:
3x = 1200
Now, let's solve for x by dividing both sides of the equation by 3:
x = 1200 / 3
x = 400
So, one scale would read 400N (x = 400), and the other scale would read twice as much, which is 800N (2x = 2 * 400 = 800).
Therefore, the scale readings are 400N and 800N.