A batter hits a baseball so that it leaves the bat with initial speed of 40 m/s, at an

angle of 60°. Tom Brady throws an incomplete pass at an initial speed of ~ 60
miles/hour (mph). When the ball was released, it’s initial velocity made an angle
of ~45° with respect to the ground.
Question: Describe the magnitudes of the ball’s velocity in the x-direction and ydirection
just after it leaves the bat?

12.250

To describe the magnitudes of the ball's velocity in the x-direction and y-direction just after it leaves the bat, we need to analyze the given information.

For the baseball:

Initial speed = 40 m/s
Angle of launch = 60 degrees

For Tom Brady's incomplete pass:

Initial speed = 60 mph
Angle of launch = 45 degrees

To find the magnitudes of velocity in the x-direction and y-direction, we can use trigonometry. The x-component of velocity represents the velocity in the horizontal direction, while the y-component represents the velocity in the vertical direction.

For the baseball:

Velocity in the x-direction = Initial speed * cos(angle of launch)
= 40 m/s * cos(60 degrees)
= 20 m/s

Velocity in the y-direction = Initial speed * sin(angle of launch)
= 40 m/s * sin(60 degrees)
= 34.64 m/s (rounded to two decimal places)

For Tom Brady's incomplete pass:

We need to convert the initial speed from mph to m/s.

Convert 60 mph to m/s:
1 mph = 0.44704 m/s (approximately)

Initial speed = 60 mph * 0.44704 m/s
= 26.82 m/s (rounded to two decimal places)

Velocity in the x-direction = Initial speed * cos(angle of launch)
= 26.82 m/s * cos(45 degrees)
= 18.95 m/s (rounded to two decimal places)

Velocity in the y-direction = Initial speed * sin(angle of launch)
= 26.82 m/s * sin(45 degrees)
= 18.95 m/s (rounded to two decimal places)

Therefore, just after the ball leaves the bat, the baseball has a velocity of 20 m/s in the x-direction and 34.64 m/s in the y-direction. For Tom Brady's incomplete pass, the ball has a velocity of 18.95 m/s in both the x-direction and y-direction.