Determine the moles of Potassium Iodate present in a 0.267 m Potassium Iodate solution assuming you have 1 kg of solvent (H2O) present.
To determine the moles of Potassium Iodate present in a 0.267 M Potassium Iodate solution, we need to use the formula:
Moles = Molarity x Volume
First, we need to calculate the volume of the solution:
Given: 1 kg of solvent (H2O) present
To convert the mass of the solvent to volume, we need to use the density of water. The density of water is approximately 1 g/mL or 1 kg/L. Therefore, 1 kg of water is equal to 1 L.
Now that we have the volume of the solution (in liters), we can calculate the moles of Potassium Iodate.
Given: Molarity (M) = 0.267 M
Volume (L) = 1 L
Moles = 0.267 M x 1 L
Moles = 0.267 moles
So, there are 0.267 moles of Potassium Iodate present in the 0.267 M Potassium Iodate solution assuming you have 1 kg of water as the solvent.