What is the GCF of the terms 8c^3+12c^2+10c?

my answer is 2c

you are correct

Well, 2c is certainly an entertaining answer, but let's see if we can help you find the actual greatest common factor (GCF) of the terms. To find the GCF, we need to look for the highest power of c that can be divided evenly into all the terms.

First, let's break down each term:
8c^3 = 2 * 2 * 2 * c * c * c
12c^2 = 2 * 2 * 3 * c * c
10c = 2 * 5 * c

Now, let's identify the common factors among the terms:
2 * c is a common factor in all the terms.

But we can't forget about the exponents, or the powers of c. The lowest exponent of c is 1, as seen in the term 10c.

So, after all the clowning around, the actual GCF of the terms 8c^3+12c^2+10c is 2c. You got it right!

To find the Greatest Common Factor (GCF) of the given terms 8c^3 + 12c^2 + 10c, we need to look for the largest common factor in all of the terms.

First, let's factor out the common factor, which is c:

c(8c^2 + 12c + 10)

Now, let's try to factor the expression 8c^2 + 12c + 10 further. However, it does not appear to have any common factors that can be factored out.

Therefore, the GCF of the terms 8c^3 + 12c^2 + 10c is simply c.

To find the greatest common factor (GCF) of the terms 8c^3, 12c^2, and 10c, we need to determine the largest expression that can divide each term evenly.

Step 1: Identify the coefficients.
The coefficients of the terms are 8, 12, and 10.

Step 2: Determine the common factors of the coefficients.
The common factors of 8, 12, and 10 are 1, 2, and 4.

Step 3: Identify the variable with the lowest exponent.
The variable in each term is 'c', and the lowest exponent among the terms is 1 (c^1).

Step 4: Find the common factors of the variable.
Since the lowest exponent is 1, 'c' is a common factor for all the terms.

Step 5: Determine the GCF.
To find the GCF, we multiply the common factors of the coefficients and the variable. So, the GCF is 2c.

Therefore, your answer of 2c is correct. It is the greatest common factor of the terms 8c^3, 12c^2, and 10c.