f(x)=3x-7 and g(X)=-2x-6. Find (f o g)(4)
im confused
(f◦g)(4) = f(g(4)) = f(-14) = -49
since g(4) = -2(4)-6 = -14
and f(-14) = 3(-14)-7 = -49
or, you can just define
(f◦g)(x) = f(g) = 3g-7 = 3(-2x-6)-7 = -6x+25
so, (f◦g)(4) = -24-25 = -49
To find (f o g)(4), we need to first find g(4) and then substitute it into the function f(x).
Given g(x) = -2x - 6, we need to find g(4):
g(4) = -2(4) - 6
= -8 - 6
= -14
Now that we have g(4) = -14, we substitute it into f(x) = 3x - 7:
(f o g)(4) = f(g(4))
= f(-14)
= 3(-14) - 7
= -42 - 7
= -49
Therefore, (f o g)(4) = -49.
To find the composition of two functions, f and g, denoted as (f o g)(4), we first need to find g(4) and then substitute that result into f.
Let's start by finding g(4):
g(x) = -2x - 6
Substituting x = 4 into g(x):
g(4) = -2(4) - 6
g(4) = -8 - 6
g(4) = -14
Now, we have g(4) = -14.
Next, we can substitute g(4) into f(x):
f(x) = 3x - 7
Substituting g(4) = -14 into f(x):
f(g(4)) = f(-14)
f(g(4)) = 3(-14) - 7
f(g(4)) = -42 - 7
f(g(4)) = -49
Therefore, the value of (f o g)(4) is -49.