A jet plane lands in an airport with a speed of 125 m/s and can accelerate uniformly at a maximum rate of -9.8 m/s2 as it comes to rest. What should be the minimum length of the runway so that the jet plane can land in the airport safely?

V^2 = Vo^2 + 2a*d

V = 0
Vo = 125 m/s
a = -9.8 m/s^2
Solve for d, the length.

To find the minimum length of the runway, we need to calculate the stopping distance of the jet plane.

First, let's determine the time it takes for the jet plane to come to rest. We can use the equation:

v = u + at

Where:
v = final velocity (0 m/s as the jet comes to rest)
u = initial velocity (125 m/s)
a = acceleration (-9.8 m/s^2)
t = time

Rearranging the equation, we get:

t = (v - u) / a

Substituting in the given values:

t = (0 - 125) / -9.8
t = 12.7551 s (approximately)

Now let's calculate the stopping distance, which is the product of the average velocity and time:

Stopping distance = (initial velocity + final velocity) / 2 * time

Stopping distance = (125 + 0) / 2 * 12.7551

Stopping distance = 3178.826 m (approximately)

Therefore, the minimum length of the runway should be approximately 3178.826 meters to ensure the safe landing of the jet plane.