A sample of gas has an initial volume of 5.9L at a pressure of 759mmHg. If the volume of the gas is increased to 8.4L , what will the pressure be?
P1V1 = P2V2
To find the pressure of the gas when the volume is increased, we can use Boyle's Law. Boyle's Law states that the pressure of a gas is inversely proportional to its volume, when temperature is constant.
Boyle's Law can be written as:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure of the gas
V1 = initial volume of the gas
P2 = final pressure of the gas (what we want to find)
V2 = final volume of the gas
Now let's plug in the given values:
P1 = 759 mmHg
V1 = 5.9 L
V2 = 8.4 L
Now we can solve for P2:
P1 * V1 = P2 * V2
759 mmHg * 5.9 L = P2 * 8.4 L
To isolate P2, we divide both sides of the equation by 8.4 L:
(759 mmHg * 5.9 L) / 8.4 L = P2
Calculating the right-hand side of the equation:
(4486.1 mmHg L) / 8.4 L = P2
Simplifying the expression:
P2 ≈ 534.3 mmHg
Therefore, when the volume of the gas is increased to 8.4 L, the pressure of the gas will be approximately 534.3 mmHg.