A sample of gas has an initial volume of 5.9L at a pressure of 759mmHg. If the volume of the gas is increased to 8.4L , what will the pressure be?

P1V1 = P2V2

To find the pressure of the gas when the volume is increased, we can use Boyle's Law. Boyle's Law states that the pressure of a gas is inversely proportional to its volume, when temperature is constant.

Boyle's Law can be written as:

P1 * V1 = P2 * V2

Where:
P1 = initial pressure of the gas
V1 = initial volume of the gas
P2 = final pressure of the gas (what we want to find)
V2 = final volume of the gas

Now let's plug in the given values:

P1 = 759 mmHg
V1 = 5.9 L
V2 = 8.4 L

Now we can solve for P2:

P1 * V1 = P2 * V2
759 mmHg * 5.9 L = P2 * 8.4 L

To isolate P2, we divide both sides of the equation by 8.4 L:

(759 mmHg * 5.9 L) / 8.4 L = P2

Calculating the right-hand side of the equation:

(4486.1 mmHg L) / 8.4 L = P2

Simplifying the expression:

P2 ≈ 534.3 mmHg

Therefore, when the volume of the gas is increased to 8.4 L, the pressure of the gas will be approximately 534.3 mmHg.