Given 3x10^6 cell/mL in 3mL. Perform dilution calculation so that you can have 1x10^5 cell/200ul.
Please help me with this question. Much appreciate.
To perform the dilution calculation, we need to determine the dilution factor required to achieve the desired concentration.
First, let's calculate the initial number of cells in the starting solution:
Initial concentration = 3 x 10^6 cells/mL
Initial volume = 3 mL
Number of cells in starting solution = Initial concentration x Initial volume
= (3 x 10^6 cells/mL) x (3 mL)
= 9 x 10^6 cells
Now, let's calculate the dilution factor needed to achieve the desired concentration:
Desired concentration = 1 x 10^5 cells/200 μl
Final volume = 200 μl
Dilution factor = Number of cells in starting solution / Number of cells in desired solution
= (9 x 10^6 cells) / (1 x 10^5 cells)
= 90
To achieve the desired concentration, you will need to dilute the starting solution by a factor of 90.
Here's how you can perform the dilution:
1. Take 1 part of the starting cell solution.
2. Add 89 parts of a diluent (e.g., buffer, water, or medium) to the starting solution.
Note: The diluent volume should be (90 - 1) parts, as per the dilution factor.
3. Mix the solution thoroughly to ensure proper dilution.
Following these steps, you will have a final solution with a concentration of approximately 1 x 10^5 cells/200 μl.