Question

Find ¡Ò[dx/(x-2)(x+3)(x-4)]

this is really confusing and I need help with it.

Answer 1

use partial fractions:

1/((x-2)(x+3)(x-4)) =

-1/10(x-2) + 1/35(x+3) + 1/14(x-4)

Now it's just a bunch of simple logs.