How much heat is contained in 100 kg of water at 60.0 °C?
To calculate the amount of heat contained in 100 kg of water at 60.0 °C, you need to use the specific heat capacity of water and the formula for calculating heat energy.
The specific heat capacity of water is 4.186 joules per gram per degree Celsius (or 4.186 J/g°C). First, you need to convert the mass of water from 100 kg to grams:
mass = 100 kg * 1000 g/kg = 100,000 g
Next, you can use the following formula to calculate the amount of heat energy (Q):
Q = mass * specific heat capacity * change in temperature
The change in temperature is the difference between the final temperature and the initial temperature. In this case, the final temperature is 60.0 °C and the initial temperature is assumed to be 0 °C (since it was not specified):
change in temperature = 60.0 °C - 0 °C = 60.0 °C
Now you can plug in the values into the formula:
Q = 100,000 g * 4.186 J/g°C * 60.0 °C
By multiplying these values, you get:
Q = 251,160,000 J
Therefore, there is approximately 251,160,000 joules of heat contained in 100 kg of water at 60.0 °C.