The radius of a iron atom is 124 pm. How many iron atoms would have to be laid side by side to span a distance of 1.75 mm?

To find out how many iron atoms would have to be laid side by side to span a distance of 1.75 mm, we need to calculate the number of atoms that fit in this distance.

First, let's convert the radius of the iron atom from picometers (pm) to millimeters (mm) since the given distance is in millimeters:

1 pm = 1 × 10^-3 mm

So, the radius of the iron atom in mm is:
Radius (mm) = 124 pm × 1 × 10^-3 mm/pm
Radius (mm) = 0.124 mm

Next, we can calculate the number of iron atoms that fit side by side in the given distance of 1.75 mm:

Number of iron atoms = Distance / Diameter

The diameter of an iron atom is twice its radius. So, the diameter of the iron atom is:

Diameter (mm) = 2 × Radius (mm)
Diameter (mm) = 2 × 0.124 mm
Diameter (mm) = 0.248 mm

Finally, we can calculate the number of iron atoms:

Number of iron atoms = 1.75 mm / 0.248 mm

Number of iron atoms = 7.056

Therefore, approximately 7 iron atoms would have to be laid side by side to span a distance of 1.75 mm.

To find out how many iron atoms would have to be laid side by side to span a distance of 1.75 mm, we need to calculate the number of atoms that fit in that distance. Here are the steps:

1. Convert the radius of the iron atom from picometers (pm) to millimeters (mm). There are 1,000,000 pm in 1 mm, so the radius in mm is: 124 pm / 1,000,000 mm/pm = 0.000124 mm.

2. Calculate the diameter of the iron atom by multiplying the radius by 2. The diameter is: 2 * 0.000124 mm = 0.000248 mm.

3. Divide the total distance (1.75 mm) by the diameter of the iron atom to find out how many atoms can fit side by side. The number of atoms is: 1.75 mm / 0.000248 mm ≈ 7056.45.

Therefore, approximately 7056 iron atoms would have to be laid side by side to span a distance of 1.75 mm.

A radius of 124 pm means a diameter of 248 pm and that is 2.48E-7 mm.

So #atoms x (2.48E-7 mm/1 atom) = 1.75 mm
Solve for # atoms.

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