in a oblique triangle ABC ,it is known that tan A=3/4,cos B=5/13 an AB=10cm

find sinC,side AC, and side BC

we know that A+B+C=180°, and we see that

A = 36.86°
B = 67.38°
So, C=75.76°

Now you can use the law of sines to find the other two sides.