The ratio of white marbles to blue marbles in Jeyan's bag is 2 to 5. If there are more than 50 marbles in the bag, what is the minimum number of marbles that can be in the bag? So what I did was add 2 and 5 which is 7 in total so I answered as 7 marbles, but it wasn't right. I'm not really sure what I should do, do I add the ratio for white marbles to blue marbles or ???

What you should do is read the problem carefully. It states that there are more than 50 marbles in the bag.

So, what is the smallest multiple of 7 that is greater than 50?

Must be 56.

To calculate the minimum number of marbles in Jeyan's bag, you need to understand the given ratio and set up an equation based on it.

The ratio of white marbles to blue marbles in Jeyan's bag is 2 to 5. This means that for every 2 white marbles in the bag, there are 5 blue marbles.

Let's assume that there are 2x white marbles and 5x blue marbles in the bag, where x is a positive integer. This allows us to keep the ratio consistent.

The total number of marbles in the bag would be the sum of the white and blue marbles:
Total number of marbles = 2x + 5x = 7x

We are given that the number of marbles is more than 50:
7x > 50

Now, we can solve this inequality to determine the minimum value of x:

7x > 50
Divide both sides by 7:
x > 50/7
x > 7.14

Since x must be a positive integer, we can round up the value of x to the nearest whole number:
x = 8

Now substitute x back into the equation to find the minimum number of marbles:
Total number of marbles = 7x = 7 * 8 = 56

Therefore, the minimum number of marbles in the bag is 56, not 7 as you initially assumed.

Remember, it's important to carefully read and understand the question and given information, and then set up the necessary equations to find the solution.