Tom has a mass of 67.2 kg and Sally has a
mass of 58.5 kg. Tom and Sally are standing
23 m apart on a massless dance floor. Sally
looks up and she sees Tom. She feels an
attraction.
If the attraction is gravitation, find its magnitude.
Assume both can be replaced by
spherical masses and that the gravitational
constant is 6.67259 × 10−11 N · m2
/kg2
.
Answer in units of N
qwdasd
186468 N
To find the magnitude of the gravitational attraction between Tom and Sally, we can use the formula for gravitational force:
F = (G * m1 * m2) / r^2
Where:
F is the magnitude of the gravitational force between the two objects,
G is the gravitational constant (6.67259 * 10^-11 N · m^2 / kg^2),
m1 and m2 are the masses of the objects (Tom and Sally),
r is the distance between the centers of the two objects.
In this case, Tom's mass (m1) is 67.2 kg, Sally's mass (m2) is 58.5 kg, and the distance between them (r) is 23 m. Plugging these values into the formula, we get:
F = (6.67259 * 10^-11 N · m^2 / kg^2) * (67.2 kg) * (58.5 kg) / (23 m)^2
Now we can calculate the magnitude of the gravitational attraction between Tom and Sally.
F = (6.67259 * 10^-11) * (67.2) * (58.5) / (23^2)
Using a calculator, we find:
F ≈ 3.60472 * 10^-7 N
So, the magnitude of the gravitational attraction between Tom and Sally is approximately 3.60472 * 10^-7 N.