what will the final temperature be of a beaker of water weighing 100g if its initial temperature is 21 ° and is heated using 125 joules in energy?
To find the final temperature of the water, we can use the specific heat capacity formula:
q = m * c * ΔT
where:
q is the heat energy absorbed or released by the substance (in joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g°C), and
ΔT is the change in temperature (in °C).
In this case, the initial temperature (T₁) is 21 °C and the heat energy (q) is 125 joules. The mass (m) of the water is 100 grams. However, we need the specific heat capacity (c) of water to complete the equation.
The specific heat capacity of water is approximately 4.18 J/g°C.
Now, rearrange the formula to solve for ΔT:
ΔT = q / (m * c)
Substituting the given values:
ΔT = 125 J / (100 g * 4.18 J/g°C)
Simplifying:
ΔT = 0.2987 °C
Finally, to find the final temperature (T₂), add the change in temperature (ΔT) to the initial temperature (T₁):
T₂ = T₁ + ΔT = 21 °C + 0.2987 °C
T₂ ≈ 21.3 °C
Therefore, the final temperature of the water will be approximately 21.3 °C.