Q. Hectors extended family was gathering a reunion. There were 8 sets of aunts and uncles. There were twice as many cousins as uncles. There were two grand parents,and than there was Hector's family of five. How many people were at the reunion?
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A. Do I just add them all to make 21? Or do I mulpite them?
8x2=16 aunts/uncles
2 x 8 = 16 twice as many cousins as uncles
2 + 5 = 7 Hector's family and grand parents
Total = 39
To determine the total number of people at the reunion, we need to calculate the number of people in each category separately and then sum them all up.
First, let's consider the aunts and uncles. There are 8 sets, so we have 8 pairs of aunts and uncles.
Next, we are told that there were twice as many cousins as uncles. Since each set of aunts and uncles consists of one uncle, we can say there were 2 times 8 = 16 cousins.
Moving on to the grandparents, we know there were two of them.
Lastly, we have Hector's family of five, which includes Hector himself, along with his parents and any siblings he might have.
Now, to find the total, we add up all the different categories.
8 sets of aunts and uncles + 16 cousins + 2 grandparents + Hector's family of 5 = 8 + 16 + 2 + 5 = 31.
Therefore, there were 31 people at the reunion.
To solve this problem, we need to break it down and calculate the number of people in each category separately. Let's go step by step:
1. Hector's family consists of 5 members.
2. There were 2 grandparents, so we add 2 to the count.
3. There were 8 sets of aunts and uncles, which means there were 8 x 2 = 16 aunts and uncles in total.
4. It is stated that there were twice as many cousins as uncles, so the number of cousins would be 16 x 2 = 32.
Now, let's calculate the total number of people at the reunion:
Hector's family (5) + Grandparents (2) + Aunts and Uncles (16) + Cousins (32) = 5 + 2 + 16 + 32 = 55
Therefore, there were a total of 55 people at the reunion.