A 10.7 kg bowling ball moves in a straight line

at 4.26 m/s.
How fast must a 2.55 g Ping-Pong ball move
in a straight line so that the two balls have
the same momentum?

M2V2 = M1V1

0.00255*V2 = 10.7*4.26
Solve for V2.

To find the speed at which the Ping-Pong ball must move to have the same momentum as the bowling ball, we can use the equation for momentum:

Momentum = mass * velocity

First, let's calculate the momentum of the bowling ball:

Momentum = 10.7 kg * 4.26 m/s

Next, let's convert the mass of the Ping-Pong ball to kilograms:

Mass of Ping-Pong ball = 2.55 g = 2.55 * 10^-3 kg

Now, we can find the velocity of the Ping-Pong ball by rearranging the equation for momentum:

Momentum of Ping-Pong ball = Mass of Ping-Pong ball * velocity of Ping-Pong ball

We want the momentum to be equal, so equating the two equations:

10.7 kg * 4.26 m/s = (2.55 * 10^-3 kg) * velocity of Ping-Pong ball

To find the velocity of the Ping-Pong ball, divide both sides of the equation by (2.55 * 10^-3 kg):

velocity of Ping-Pong ball = (10.7 kg * 4.26 m/s) / (2.55 * 10^-3 kg)

Now, let's calculate the velocity:

velocity of Ping-Pong ball = (10.7 * 4.26) / (2.55 * 10^-3) m/s

Simplifying the equation:

velocity of Ping-Pong ball = 18.00 m/s

Therefore, the Ping-Pong ball must move at a speed of 18.00 m/s in a straight line to have the same momentum as the bowling ball.