A submarine dives 196.0 m at an angle of 18.0 ◦ below the horizontal. What is the horizontal component of the submarine’s displacement? Use the coordi- nate system where positive x is to the right and positive y is up. Answer in units of m.
x=106.64
y=-124.58
To find the horizontal component of the submarine's displacement, we need to calculate the component of the displacement vector that is parallel to the horizontal axis.
Given that the submarine dives at an angle of 18.0 degrees below the horizontal, we can visualize the displacement vector as having two components: a vertical component (parallel to the y-axis) and a horizontal component (parallel to the x-axis).
To find the horizontal component, we can use trigonometry. We know the magnitude of the displacement, which is given as 196.0 m. We also know the angle of 18.0 degrees.
Using trigonometry, we can use the cosine function to find the horizontal component:
Horizontal Component = Displacement * cos(angle)
Substituting the values into the formula:
Horizontal Component = 196.0 m * cos(18.0 degrees)
Now, let's calculate it:
Horizontal Component = 196.0 m * cos(18.0 degrees)
Using a calculator or the cosine table, we find:
Horizontal Component ≈ 187.50 m
Therefore, the horizontal component of the submarine's displacement is approximately 187.50 m.
196m[-18o]
X = 196*Cos(-18) =
Y = 196*sin(-18) =