12m+12=6(3m+3)
My answer is -6= -6 which is identity ??? Or is it null or empty??
12m +12 = 18m + 18
Subtract 12m and 18 from both sides of the equation.
-6 = 6m
-1 = m
Thanks
To solve the equation 12m + 12 = 6(3m + 3), we will simplify both sides of the equation.
First, distribute the 6 to the terms inside the parentheses on the right side:
6(3m + 3) = 18m + 18
Now, the equation becomes:
12m + 12 = 18m + 18
Next, we want to isolate the variable (m) on one side of the equation. We can do this by moving the terms involving m to one side and the constants to the other side.
Subtract 18m from both sides:
12m - 18m + 12 = 18m - 18m + 18
-6m + 12 = 18
Finally, subtract 12 from both sides:
-6m + 12 - 12 = 18 - 12
-6m = 6
To solve for m, we will divide both sides of the equation by -6:
-6m/-6 = 6/-6
m = -1
Therefore, the solution to the equation is m = -1.