A 50 g lunch pail is lifted up 500 m. If the work required to do this was 1450 J, what's the acceleration?
W= mad
1450 = (0.05 kg)(a)(500m)
1450 = 250a
5.8 m/s^2 = a
If a 750 g mass is accelerated at a rate of 11.0 m/s^2 for a distance of 3.0 m, how much work was done?
W = mad
W = (0.75kg)(11.0m/s^2)(3.0m)
W = 24.75 J
W= 24.8 J
Thanks!
but you forgot the work done against gravity
m g * 500 = .05 * 9.81 * 500 = 245 J
1450 - 245 = 1204 J
so
1204 = .05 * a * 500
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The second one looks ok
Thanks!
You're welcome! To find the acceleration in the first question, you used the equation W = mad, where W is the work done (in joules or J), m is the mass (in kilograms or kg), a is the acceleration (in meters per second squared or m/s^2), and d is the distance (in meters or m). By rearranging the equation, you were able to solve for the acceleration using the given values:
W = mad
1450 J = (0.05 kg)(a)(500 m)
1450 J = 250a
a = 1450 J / 250
a = 5.8 m/s^2
In the second question, you were asked to find the work done. Again, you used the equation W = mad, but this time you were given the mass (0.75 kg), acceleration (11.0 m/s^2), and distance (3.0 m). Plugging these values into the equation, you were able to calculate the work done:
W = mad
W = (0.75 kg)(11.0 m/s^2)(3.0 m)
W = 24.75 J
Therefore, the work done in this scenario is 24.75 J or approximately 24.8 J (rounded to one decimal place).