Peter and Paul are heading towards the same destination 25 km away. Peter walks at 5 km/h while paul cycles 4 times as faster. If both start off from the same place at the same time, Paul will arrive _______ hours earlier than Peter. Express your answer to the nearest hundredths.

25/5 = 5 hours

5 * 4 = 20 km/h

25/20 = 1.25 hours

5 - 1.25 = ?

To find out how many hours earlier Paul will arrive than Peter, we need to calculate the time it takes for each of them to reach the destination.

The first step is to find the time it takes for Peter to travel 25 km at a speed of 5 km/h. We can use the formula:

Time = Distance / Speed

So, for Peter:
Time = 25 km / 5 km/h
Time = 5 hours

Now, we need to find Paul's speed. It is mentioned that Paul cycles 4 times as fast as Peter. Since Peter's speed is 5 km/h, Paul's speed will be:

Paul's speed = 5 km/h * 4
Paul's speed = 20 km/h

Next, we can calculate the time it takes for Paul to travel 25 km at a speed of 20 km/h:

Time = Distance / Speed
Time = 25 km / 20 km/h

To express the answer to the nearest hundredths, we need to divide the distance by the speed:

Time = 25 / 20
Time = 1.25 hours

Now, to find out how many hours earlier Paul will arrive than Peter, we subtract the time it takes for Peter from the time it takes for Paul:

Time difference = Time (Paul) - Time (Peter)
Time difference = 1.25 hours - 5 hours

To the nearest hundredths, the time difference is approximately:

Time difference = -3.75 hours ≈ -3.75

So, Paul will arrive approximately 3.75 hours earlier than Peter.