How many atoms are in LiBr2 show in the reaction side?
LiCl (22g) + Br2 (30g)
To determine the number of atoms in LiBr2 on the reaction side, we need to find the molar mass of LiBr2.
First, we need to find the molar mass of Li. The atomic mass of Li is approximately 6.94 g/mol.
Next, we find the molar mass of Br. The atomic mass of Br is approximately 79.90 g/mol.
To calculate the molar mass of LiBr2, we add the molar masses of Li and Br together:
Molar mass of LiBr2 = (Li molar mass) + (2 x Br molar mass)
= 6.94 g/mol + (2 x 79.90 g/mol)
= 166.74 g/mol
Now that we have the molar mass of LiBr2, we can determine the number of moles of LiBr2 by dividing the given mass by the molar mass.
Moles of LiBr2 = mass / molar mass
= (22 g LiCl + 30 g Br2) / 166.74 g/mol
= 0.3188 mol
Since there is 1 mole of LiBr2 for every mole of LiBr2, the number of atoms in LiBr2 is equal to Avogadro's number, which is approximately 6.022 x 10^23.
Therefore, there are approximately 0.3188 x 6.022 x 10^23 atoms of LiBr2 on the reaction side.