A tension force of 2.50 N acts horizontally on a 2.00 kg block. The block accelerates at 0.750 m/s2. What is the force of kinetic friction?

2 x .75, = 1.5N
(2.5 - 1.5) = 1N?????

To find the force of kinetic friction, we need to consider Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the net force is the difference between the applied force (tension force) and the force of kinetic friction.

Given:
Tension force = 2.50 N
Block mass = 2.00 kg
Acceleration = 0.750 m/s^2

Step 1: Calculate the net force
Net force = mass x acceleration
Net force = 2.00 kg x 0.750 m/s^2
Net force = 1.50 N

Step 2: Calculate the force of kinetic friction
Force of kinetic friction = Tension force - Net force
Force of kinetic friction = 2.50 N - 1.50 N
Force of kinetic friction = 1.00 N

Therefore, the force of kinetic friction acting on the block is 1.00 N.

To find the force of kinetic friction, we need to use Newton's second law of motion. Newton's second law states that the net force acting on an object is equal to the product of the mass of the object and its acceleration. Mathematically, it can be written as:

Fnet = m * a

Here, Fnet is the net force, m is the mass of the object, and a is the acceleration.

We are given the mass of the block (m = 2.00 kg) and the acceleration (a = 0.750 m/s^2). The net force acting on the block is equal to the tension force (2.50 N) minus the force of kinetic friction. So we can write:

Fnet = T - fk

Plugging in the values, we have:

m * a = T - fk

Rearranging the equation, we get:

fk = T - m * a

Substituting the given values, we get:

fk = 2.50 N - (2.00 kg * 0.750 m/s^2)

fk = 2.50 N - 1.50 N

fk = 1.00 N

Therefore, the force of kinetic friction is 1.00 N.

Fnet=Ft-Ff

m*a=Ft-Ff

2.00kg*0.750=2.50N-Ff

1.5N=2.50N-Ff

1.5N/2.50N=Ff

Ff=0.6N