Solve the following system of equations using both substitutio and elimination
y=-x+4
y=-2x-4
Do I do what I do with the previous problems
I did the earlier ones with elimination
here is substitution
y = (-x+4)
so
(-x+4) = -2x - 4
x = -8
then go back and get y
y = -x + 4 = 8+4 = 12
for elimination subtract as is
y=-x+4
y=-2x-4
-------------
0 = 1 x + 8
so
x = -8
then get y = 8+4 = 12
I know where you get 1x but where did you get the +8 from
On the Elimination part
y = -x + 4
y = -(-8) + 4
So you first do 2x-x and get 1x. What do you do after that? Because I see it says 0=1 x + 8 but I still don't know how to get it
y=-x+4
y=-2x-4
------------- SUBTRACT these two equations
0 = -x -(-2x) + 4 - (-4)
0 = -x + 2x + 4 + 4
0 = x + 8
x = -8