5x-4y=10
-10x+2y=-20
If x is 2 what would y be? When I plug it in I get y as 0
10 x - 8 y = 20
-10 x + 2 y = -20
----------------- add
6 y = 0
y = 0
if y = 0
5 x = 10
x = 2
so the two lines intersect at (2 , 0)
Ty
You are welcome.
To solve the system of equations:
5x - 4y = 10 ...(Equation 1)
-10x + 2y = -20 ...(Equation 2)
You can substitute the value of x as 2 in both equations and solve for y.
For Equation 1:
5(2) - 4y = 10
10 - 4y = 10
-4y = 10 - 10
-4y = 0
Divide both sides of the equation by -4:
-4y / -4 = 0 / -4
y = 0
For Equation 2:
-10(2) + 2y = -20
-20 + 2y = -20
2y = -20 + 20
2y = 0
Divide both sides of the equation by 2:
2y / 2 = 0 / 2
y = 0
Therefore, when x is 2, y is indeed 0.